Question

A rocket is moving vertically upward with speed 500 kilometre per hour it is rejecting product of combustion with speed 2000 kilometre per hour with respect to find out actual product of combustion.​

Answer 1

Answer:

Given

Speed of moving rocket = 500 kilometre per hour

Speed of ejection product combustion = 2000 kilometre per hour with respect to itself

A.T.Q.

By Concept of relative speed

=> Vr = Vj + VP

=> 2000 = 500 + Vp

=> Vp = 1500 km/ h

Hence

Speed of combustion product is 1500 km per hour.

Answer 2

Explanation:

GIVEN,

Speed of moving rocket = 500 km/h

Speed of ejection product combustion = 2000 km/h

A.T.Q.

$\: formula=> Vr = Vj + VP \\ \\ putting \: the \: value \\ </p><p></p><p>=> 2000 = 500 + Vp \\ </p><p></p><p>=> 2000 - 500 = vp \\ = > 1500 = vp\\ vp = 1500 \: \frac{km}{h} </p><p> </p><p> \:$