Question

A rocket is projected vertically upward with acceleration 10m/s^2 after 1 second its fuel tank become empty find the maximum height gain by the rocket and time of flight.

Answer 1

The distance travelled by the rocket in 1 minute (60 s) with a = 10 m / s^2 upward is

h= 1/2 × 10 × 60^2

= 18000 m

= 18 km

Velocity acquired =>

v = 10 × 60

= 600 m / s

now here a=10m/s^2

if we take acceleration due to gravity=10m/s^2

then same time is taken by the rocket when he will goes down i.e 1min

so total time taken 1+1=2min=120sec

so that is the answer

maximum hieight =18km

total time=2min

hope i got the correct answer 4u