Question

A rocket is shot staright up from the earth, with a net acceleration(= acceleration by the rocket engine minus gravitional pull back) of 7t m/sec^2 during the initial stage of flight untile engine cut out at t=10 sec. how high will it go, air resistance neglected

Answer 1

h=ut + 1/2gt²

0×60 +1/2 × 10 × 60² = 1800m - (i)

and velocity acquired will be

v=u + at

= 0 + 10 × 60 = 600m/s

(ii)

Step-by-step explanation:

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