Question

A rocket motor consume 100 kg of fuel per second, exhausting it with a speed of 6 x 104 ms. What thrust is exerted the rocket ? What will be the velocity of rocket at the instant its mass is reduced (1/40)th of its initial mass ? Take initial velocit of rocket as zero. Neglect gravity. Dm

Answer 1

=> Here, A rocket motor consume 100 kg of fuel per second, exhausting it with a speed of 6 x 104 ms.

∴ dm/dt = 100kg/s

u = 6* 10⁴ m/s

Thus, Thrust F = u*dm/dt = 6*10⁴*100

= 6×10⁶ N

(ii)  The velocity of rocket when its mass is reduced (1/40)th at the instant  of its initial mass:

Here, m= 1/40 * m₀

m₀/m = 40

velocity, υ = (2.303)u log₁₀ (m₀/m)

= 2.303 × 6 × 10⁴ × log₁₀ 40

= 2.303 × 6 ×10⁴ ×1.602

= 22.13×10⁴ m/s .

Answer 2

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