Physics, asked by shresth22, 11 months ago

A rocket of mass 2000 kg is ejecting the gases at
the rate of 50 kg/sec with speed of 20 m/sec in
gravity free space. Find the acceleration of rocket
at 2 sec.​

Answers

Answered by qwtiger
13

Answer:

The acceleration of rocket  at 2 sec 0.526 m / s^2

Explanation:

According to the problem the mass of the rocket  is ejected at a rate with the stated speed.

Therefore, let the momentum,= q

q can be calculated by multiplying the mass with the velocity

Now, change of momentum can be calculated from the force acting on a body

Let force= f

Therefore,f = dp / dt.

Thus, f = m × (dv / dt ) + v × ( dm / dt )

let the rocket is moving in a constant velocity

dv / dt = 0

Therefore,

f = v × ( dm / dt )

As the rate of ejection of mass ( dm / dt ) = 50 kg / s

and the speed is, v = 20 m / s

Therefore the  force acting on the rocket

                         = 20 × 50   = 1000 N

Now, effective mass of the rocket after 2 s ( M )

                                                      = 2000 - 2 × 50  = = 1900 kg

Therefore the acceleration of rocket at 2 sec is = f / m

                                                                             = 1000 / 1900

                                                                               = 0.526 m / s^2

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