Question

A rocket of mass 3(106kg)takes off from a launching pad and acquired a vertical velocity of lkm/s at an altitude of 25km calucate (1) potential energy (2)kinetic energy ( g 9.8m/S2)

Answer 1

given mass(m)=3*106=318kg
velocity(v)=1km/s=1000m/s
height=25km=25*10^3m
potential energy=mgh
                             =318*9.8*25*10^3
                              =7.79*10^7 joules
kinetic energy=1/2mv2
                         =1/2*318*1000^2
                          =1.59*10^8 joules