Question

A rocket ship starts from rest and turns on its forward booster rockets, causing it to have a constant acceleration of 4 m/s2 rightward .After 3s, what will be the velocity of the rocket ship?

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 0 (As rocket ship starts from rest)

Acceleration, a = 4 m/s²

Time taken, t = 3 seconds

To Find,

Final velocity, v = ??

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 4 × 3

⇒ v = 4 × 3

⇒ v = 12 m/s

Hence, the velocity of the rocket ship is 12 m/s.

Answer 2

Given:-

• Initial velocity of rocket ship (u) =0m/s.
• Acceleration of rocket ship (a) =4m/s²
• Time taken (t) =3s

To Find:-

• Final velocity of rocket ship (v)

Solution :-

By using 1st equation of motion

☛ v= u+at

☛v=0+4×3

☛ v=12m/s.

∴The Final velocity of rocket ship is 12m/s.

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Some other equation of motion are

1. v=u+at
2. S=ut+1/2at²
3. v² =u² +2as