Question

A rocket ship starts from rest and turns on its forward booster rockets, causing it to have a constant acceleration of 4 m/s^2. what will be the velocity of the rocket ship after 3 s ?
Ans: __________ s.

Answer 1

Initial velocity , u = 0 m/s

∵ started from rest

Acceleration , a = 4 m/s²

Final velocity , v = ? m/s

Time , t = 3 s

Apply 1st equation of motion ,

$:\implies \sf \pink{v=u+at}\ \; \bigstar$

$:\implies \sf v=(0)+(4)(3)$

$:\implies \sf v=0+12$

$:\implies \sf \green{v=12\ m/s}\ \; \bigstar$

So , Velocity of the rocket ship after 3 s is 12 m/s .

More Info :

Equation's of motion :

→  v = u + at

→  s = ut + ¹/₂ at²

→  v² - u² = 2as

Answer 2

GIVEN :-

• A ʀᴏᴄᴋᴇᴛ sʜɪᴘ sᴛᴀʀᴛs ғʀᴏᴍ ʀᴇsᴛ .

• Aᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴏғ ᴛʜᴇ ʀᴏᴄᴋᴇᴛ = 4 ᴍ/s²

• Tɪᴍᴇ = 3 s

TO FIND :-

• Tʜᴇ ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴛʜᴇ ʀᴏᴄᴋᴇᴛ sʜɪᴘ ᴀғᴛᴇʀ 3s .

SOLUTION :-

Wᴇ ʜᴀᴠᴇ ᴋɴᴏᴇ ᴛʜᴀᴛ,

$\huge\purple\star$ $\huge\bf\pink{v\:=\:u\:+\:at\:}$

Wʜᴇʀᴇ,

• $\bf\red{v}$ = Fɪɴᴀʟ ᴠᴇʟᴏᴄɪᴛʏ

• $\bf\red{u}$ = ɪɴɪᴛɪᴀʟ ᴠᴇʟᴏᴄɪᴛʏ

• $\bf\red{a}$ = ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ

• $\bf\red{t}$ = ᴛɪᴍᴇ

Aᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴛʜᴇ ǫᴜᴇsᴛɪᴏɴ,

• ᴜ = 0 ᴍ/s [sᴛᴀʀᴛs ғʀᴏᴍ ʀᴇsᴛ]

• a = 4 m/s²

• t = 3 s

➳ v = 0² + 4 × 3

➳ v = 0 + 12

➳ v = 12 m/s²

$\huge\red\therefore$ Tʜᴇ ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴛʜᴇ ʀᴏᴄᴋᴇᴛ sʜɪᴘ ᴀғᴛᴇʀ 3s is "12 m/s²"