Question

A rocket starts from rest and moves up with acceleration 2g. After time t, engine is switched off.
Up to what maximum height from ground does the rocket reach?​

Answer 1

Answer:

concept are attached, rest calculation is:

Velocity when the engine is switched off

v=19.6∗5=9.8m/s

hmax=h1+h2

where, h1=21at2&h2=2av2

hmax=21∗19.6∗5∗5+2∗9.898∗98

=245+490=735m

B is correct answer

please mark my answer as brainlist.