Question

A rocket toy has a hemispherical base, a cylindrical body and a conical nose cap. The rocket is 20 CM long. The hemisphere,tye cylinder and the cone have a base diameter 3 CM each and the body of the cylindrical box is 8 CM long. Find the volume of the toy rocket.

Answer 1

Answer:

this is from surface area and volume

Answer 2

The volume of the toy is 88.375 cm³

Step-by-step explanation:

diameter = 3 cm

radius = 1.5 cm

height of the toy = 20 cm

height of the cylinderical box (H) = 8 cm

height of the hemispher= 1.5 cm

height of the cone = 20-(8+1.5) = 10.5 cm

now , volume of toy  = volume of cone + volume of cylinder + volume of hemisphere

$= \frac{1}{3}\pi r ^2 h +\pi r ^2 h+ \frac{2}{3}\pi r ^3\\\\=\pi r ^2(\frac{1}{3}h +H+\frac{2}{3}r)\\\\= \frac{22}{7}\times1.5 \times 1.5 (\frac{1}{3}\times 10.5+8+\frac{2}{3}\times 1.5)\\\\=7.07 (3.5+8+1)\\\\=7.07(12.5)\\\\=88.375 cm^3$

Hence , The volume of the toy is 88.375 cm³

#Learn more:

A wooden toy rocket is in the shape of a a cone mounted on a cylinder.The height of the entire rocket is 26 cm,while the height of the conical is 6 CM, the base of the conical portion has a diameter of 5 cm,

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