Physics, asked by Ahon, 1 year ago

A rod 1 metre long is moving along its lenght with a velocity of 0.6c .Calculate its lenght as it appear to an observer.
1) On the earth.
2) Moving with rod itself.

Answers

Answered by physicspo
4
length= .8m and 1m resp
Attachments:

Ahon: hi,sir...i have a question.!
physicspo: shoot
Ahon: how is it different to an observer on the earth and moving with rod itself.
physicspo: clearly state your query pls
Ahon: are the value Lo will b same for both(1&2) question?
physicspo: no... absolutely not
Ahon: so.,can u pls make me clearify.!
Ahon: whts the value for Lo in 1 and Lo 2.?
physicspo: its the concepts of relativity
physicspo: rod moving with 0.6c will get proportionately smaller length to an observer on earth
Answered by jitushashi143
4

Answer:

(1) The length of the rod observed is 0.8 m

(2) The length of the rod observed is 1 m

Explanation:

The length of the rod L_{o}=1 m

The velocity of the rod is v=0.6 c

The speed of light is c

PART(A)

As the velocity of the rod is very high

So if we observe the rod from the other reference of frame then the length of the rod will be shorter than its original length due to theory of relativity.

The relative formula for the length is,

L=L_{o}\sqrt{1-\dfrac{v^2}{c^2}}\\L=1\sqrt{1-\dfrac{(0.6c)^2}{c^2}}\\L=\sqrt{1-0.6^2}\\L=\sqrt{1-0.36}\\L=\sqrt{0.64}\\L=0.8\ m

PART(B)

If the observer is moving with the rod itself means that the rod is at same reference of frame then the length of the rod observed by the observer is same as L_{o}=1\ m

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