Question

a rod, 11/2m long, is lowered into a swimming pool. if 13/33 part of the rod is visible above water when one end of the rod touches the bottom of the pool, how deep is the water?

Answer 1

Let the depth of pool = x
x + (11/2)*(13/33) = 11/2
x + 11*13/2*33 = 11/2
x + 13/6 = 11/2
x = (11/2) - (13/6)
x = 33-13/6
x = 20/6
x = 10/3 m

Answer 2

Answer:

$3 \frac{1}{3}$

meter is the correct answer