A rod 1m long is acted upon by a couple.the moment of the couple is 17.32 Nm.if the forces at each end of the rod are inclined at 30°,find the magnitude of each force.
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Answer:
torque = r x F = r F sinα
17.32 = 1 × F sin30
F = 2×17.32
F = 34.64 N
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