Question

A rod 28 centimeter long is to be bent to make a rectangle How about a rectangle Of digonal 14 centimeter

Answer 1

Answer:

Perimeter of the rectangle = Length of the wire 2(Length + Breadth) = 34

⇒ Length + Breadth = 17

Let the length of the rectangle be x cm.

⇒ Breadth of the rectangle = (17 - x) cm.

Using Pythagoras theorem,

x

2

+(17−x)

2

=13

2

x

2

+289−34x+x

2

=169

2x

2

−34x+120=0

x

2

−17x+60=0

Discriminant =b

2

−4ac=289−240=49

x=

2a

−b±

b

2

−4ac

=

2

17±

49

=

2

17±7

=12or5

When length, x = 12 cm, breadth, 17 - x = 5 cm

When length, x = 5 cm, breadth, 17 - x = 12 cm

Thus, the lengths of the sides of the rectangle are 12 cm and 5 cm.

HOPE ITS HELP YOU......