Math, asked by mosesmark, 1 year ago

A rod 5 1/2m long ,is lowered into a swimming pool. If 13/33 part of the rod is visible above the water when one end of the rod touches the bottom of the pool, how deep is the water?

Answers

Answered by nirupamsuraj81p15xfx
2
Out of 33, 13 parts is visible.
So, out of 5.5, 5.5×13/33 =2
16 parts is visible.
So, the dipped part = depth of pool = 5 - 2.16 = 2.84 m
Answered by brlakkappa018
0

Answer:

answer is 2.84 m

Step-by-step explanation:

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