A rod ab is 8 m long and has got a weight of 10 kg at
a. The fulcrum is 3 m away from
b. Calculate the load at b, if the rod is in balanced condition
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Given :
The length of rod = 8 m .
A weight of 10 kg is put at A.
Fulcrum is 3 m away from B .
Let the weight of load at B be x .
Distance of A from fulcrum = 8 m - 3 m
= 5 m
By principle of moments :
Sum of clockwise moments = sum of anti-clockwise moments .
Hence we can write that :
5 m × 10 kg = x × 3 m
= > 50 kg m = 3 x m
= > 3 x = 50 kg
= > x = 50/3 kg
= > x = 16.666 kg
= > x = 16.67 kg
ANSWER :
The load at B would be 16.67 kg
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