Question

A rod AB is slipping on a frictionless surface as shown. It acceleration of A is 10 m/s? downward, the
acceleration of B will be
A
10-31
pa
(1) 10 coto
(2) 10 tan 0
(3) 10 sin 0
(4) 10 cose​

Answer 1

Answer:

2.10 tan0

Explanation:

(opposite by hypotenuse) the relation betweenthe block and the wedge is tan0

Answer 2

Given:

A rod AB is slipping on a frictionless surface

acceleration of A is 10 m/s

Find acceleration of B=?

Let Acceleration = a

So we can write acceleration of A and B as:

$a_{A} = 10 \\a_{B=?}$

$a_{A} \ cos\theta = a_{B} \ sin\theta$

$a_{B} = a_{A} \times \frac{cos\theta}{sin\theta}$

$a_{B} = 10\ cot\theta$

The correct option is "1"

Hence the answer is $a_{B} = 10\ cot\theta$