A rod AB of length = 1m and mass m = 2 kg is pinned to a
vertical shaft and a massless string is tied with the shaft at the
lower end of the rod (length of the string is -m) as shown in
figure. If the shaft starts rotating with a constant angular velocity
m = 5 rad/sec. Then find the tension in the string.
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The tension in the string is 8 N-m
Explanation:
dt = dF.g
dx = dmxω^2
dτ = xa^2.x
dτ = x^2 ω^2 / tanθ dm
dτ = x^2 ω^2 / tanθ
dτ = x^2 ω^2λ / tanθ
τ = ω^2λ / tanθ sinθ
After putting the values we get.
τ = 2 x 4^3 / 4^2
τ = 4 x 2 = 8 N-m
Balancing torque against tangent point.
mg x 2/5 + T x 2/5 = τ
8 + 3T / 5 = 8
T = 0
Thus the tension in the string is 8 N-m
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