Question

A rod AB of length 2m and mass 2kg
is lying on smooth horizontal x - y
plane with its centre at origin O as
shown figure. An impulse J of
magnitude 10 Ns is applied
perpendicular to AB at A. Then​

Answer 1

Answer:

1/3 .l think this is the answer for these question

Answer 2

Your question is incomplete without the options and diagram.

The correct question would be

A rod AB of length 2m and mass 2kg is lying on smooth horizontal x - y plane with its centre at origin O as shown figure. An impulse J of

magnitude 10 Ns is applied perpendicular to AB at A. Then the distance of p from the centre of the rod after the rest would be __________.

Choose the correct option

i) 2/3 m.

ii) 1/4 m.

iii) 1/3 m.

iv) 1/2 m.

(Refer the attachment for the diagram)

The correct option is iii) 1/3 m.

Then the distance of p from the centre of the rod after the rest would be 1/3m.

v = j/m = 10/2 = 5m/s.

ω = j (1/2) / 1

= j1 / 2 (m /1 ^ 2) ^ 2

= 6j / m1

= 6*10/2*2

= 15 rad/s

At a distance r from the centre v, r and ω should cancel each other at the point P.

Hence

r = v/ω

= 5/15

= 1/3 m.

Therefore

The correct option is iii) 1/3 m.