Question

A rod can slide between two perpendicular wall as shown. If the end A moves with speed v, then find the speed of the centre of the rod in terms of theta.​

Answer 1

Answer:

Explanation:In this question have you had tried mid point theorem at the point of 90° draw a line stroight towards the mid of A and B after this name the point and use formula √a^2+b^2 you will get your answer

Answer 2

Answer:

$V_{Cm}=\dfrac{vxsin\theta }{y}$

Explanation:

Velocity of point A = v m/s

From the diagram

I =Instantaneous center (rod rotates about this center)

Lets take ω is the angular velocity of rod,so

v =  ω . IA

v =  ω . y

ω = v /y              -------------1

OA = x  So, IB = x

IC = x sinθ

Velocity of center of mass Vcm

Vcm=  ω . IC

VCm=  ω . x sinθ

Vcm=  v x  sinθ /y

$V_{Cm}=\dfrac{vxsin\theta }{y}$