Question

A rod has mass M and length 2L it's moment of inertia about an axis passing through its end and perpendicular to its length is​

Answer 1

Answer:

For the rod of mass M and length l, I=Ml2/12. Using the parallel axes theorem, I'=I+Ma2 with a=l/2 we get,

I.=Ml212+M(l2)2=Ml23

We can check this independently since I is half the moment of inertia of a rod of mass 2M and length 2l about its midpoint,

I.=2M.4l212×12=Ml23

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