Question

A rod having initial length 10 m is pulled by a force of 10
KN. If the final length of the rod is 10.2 m, then the strain
of the bar is equal to-​

Answer 1

Given:

A rod having initial length 10 m is pulled by a force of 10 KN. The final length of the rod is 10.2 m.

To find:

Strain of the bar?

Calculation:

• Strain is a dimensionless quantity calculated by the ratio of change in length of an object over the initial length of that object.

Let strain be $\mu$

$\rm \therefore \mu = \dfrac{\Delta L}{L}$

$\rm \implies \mu = \dfrac{10.2 - 10}{10}$

$\rm \implies \mu = \dfrac{0.2}{10}$

$\rm \implies \mu = 0.02$

So , strain of the bar is 0.02.

• Please note that STRAIN doesn't have any unit, because it is a ratio of similar quantities.