Physics, asked by rukaiyabano, 5 hours ago

A rod is 0.5m long and 5 mm in diameter. It is stretched 0.06mm by a force of 3kN. Calculate stress and strain.​

Answers

Answered by rehanbinyasin
6

Answer:

stress is 152 MN and strain is 0.00012

Explanation:

stress is equal to F/Area. so 3000/pir*radius^2 3000/3.14*0.0025^2 so 3000/ 0.000019625

hence stress = 152866242 N/m^2 or 152MN

strain = chanhe in lengeth / original length

strain = .06/500 = 0.00012

enjoy dude

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