Question

a rod is bent into a circle of radius 2m. the rod has uniform linear charge density 1C/m. the electric potential at the center is?

Answer 1

See..its just asking electric potential of circle at center. So use formula and get the answer... ok which is E=Kq/r.

For charge... we know Liner charge density= Charge / length=q/2
and density is 2
so q/2=2 then q=4 C
E= 9×(10^9)×4/2
E=18 ×10^9 V

Answer 2

Answer:

The electric potential at the center is $5.65\times10^{10} V$.

Explanation:

Given that,

radius = 2 m

Charge density = 1 C/m

The linear charge density is

$\lambda= \dfrac{q}{l}$

Here, q = charge

l = length

Now the charge will be

$q =\lambda\times l$

$q =2\pi r$

$q= 4\pi\ C$

The electric potential at the center is

$V=\dfrac{kq}{r}$

$V \dfrac{9\times10^{9}\times4\pi}{2}$

$V=\dfrac{9\times10^{9}\times4\times3.14}{2}$

$V=5.65\times10^{10} V$

Hence, The electric potential at the center is $5.65\times10^{10} V$.