Physics, asked by Vickyvic3612, 11 months ago

A rod is inserted as the core in the current-carrying solenoid of the previous problem. (a) What is the magnetic intensity H at the centre? (b) If the magnetization I of the core is found to be 0.12 A m−1, find the susceptibility of the material of the rod. (c) Is the material paramagnetic, diamagnetic or ferromagnetic?

Answers

Answered by bhuvna789456
14

Explanation:

(a) Magnetization intensity ,

H=1500 \mathrm{A} / \mathrm{m}\\

  • The end results may be overlooked as the solenoid and the rod are large and we are focused in the intermediate magnetic power.
  • The rod's sole role in the magnetic area of the solenoid is to induce magnetisation in the rod, depending on the magnetic properties of the rod.
  • There is no influence of the rod on the centre's magnetic strength.  

(b) Core magnetization,

I=0.12 \mathrm{A} / \mathrm{m}

We know that  

I=\chi H_{\iota}

where

χ The susceptibility of the rod material.

\chi=\frac{I}{H}

  =\frac{0.12}{1500}        

  =0.00008

  =8 \times 10^{-5}

(c) The material has paramagnetic effect

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