Question

a rod of 1m long is moving along it's length with a velocity of 0.6c.calculate it's length as it appear to an observer on the earth and moving with the rod​

Answer 1

Answer:- 0.8 meter.

Formula:-

for length contraction is,

$l = l0 \sqrt{1 - \frac{ {v}^{2} }{ {c}^{2} } }$

where,

l = new Length (in meter)

lo = Original length (in meter)

v = speed of object (in m/s)

c = speed of light (in m/s)

Given,

lo = 1 meter .

v = (0.6c) .

Solution:-

$l = \sqrt{1 - \frac{ {0.6c}^{2} }{ {c}^{2} } } \\ = > l = \sqrt{1 - {0.6}^{2} } \\ = > l = \sqrt{0.64} \\ = > l = 0.8m$

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