A rod of length 1 m having cross-sectional area
0.75 m' conducts heat at 6000 JS-. Then the
temperature difference acorss the rod is, if
K-200 Wm'K!
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using formula ,
power = KA ∆T/∆x
where , A is cross sectional area of rod.
K is thermal conductivity , ∆T is change in temperature and ∆x is seperation between terminals of different temperatures.
here, power = 6000J/s
∆x = 1m
A = 0.75 m²
K = 200 W/m.°C
so, 6000 = 200 × 0.75 × ∆T/1
or, 30 = 0.75 × ∆T
or, ∆T = 3000/75 = 40
hence, change in temperature is 40°C
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