a rod of length 10cm is placed along principal axis of concave mirror of focal length 10cm such that the center is 25cm from the pole find the lenght of the image
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Answer:
Correct option is
C
5 cm
The position of image of nearer end to mirror can be found out using mirror equation,
v
1
+
u
1
=
f
1
⟹
v
1
1
=
−20
1
−
−10
1
⟹v
2
=−20
Similarly position of image of farther end to mirror can be found out as
=
v
2
1
=
−(10+20)
1
−
−10
1
⟹v
2
=−15
Hence the length of the image =20cm−15cm=5cm
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