A rod of length 1m is held vertically with one end on he floor and left to fall
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please complete the question !!!!!!
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If the complete question is given in explanation if i m right
If mass of bead is m;
mg-µN=ma
Now, N=pseudo force due to acceleration of train, which is equal to 4m Newton.
=> mg-µ(4m)=ma
=> g-4µ=a
=> a=8ms-2
Using, second equation of motion:
1=0.5(8)t2
T=0.5sec
Correct answer is 0.5sec
Explanation:A thin rod of length 1 m is fixed in a vertical position inside a train, which is moving horizontally wit
constant acceleration 4 m/s2. A bead can slide on the rod, and friction coefficient between them is 1/2.
If the bead is released from rest at the top of the rod, find the time when it will reach at the bottom
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