Question

A rod of length 1m is kept inclined at an angle of 60° with the uniform magnetic field of strength 0.5 tesla. If the rod is moved with a velocity 10 m/s perpendicular to the field, then the induced e.m.f. is
1) 2.5 v
2) 4.3 v
3) 7.5 v
4) 10v​

Answer 1

Answer:

opt 2

Explanation:

e=blvsin(theta)

=0.5×1×10×(3)‐²/2

=4.3 v