Question

A rod of length 4 m is suspended from two wires
as shown in figure. One of them is made of steel
and other of copper of cross-sectional area 10-?m
and 4 x 10-2 m2. Find distance x if equal stress is
experienced by both the wires (Yster = 2 x 1011 N/m²
and Y Copper = 1.1 x 1011 N/m2
Steel
Copper
w​

Answer 1

Answer:x=3.2

Explanation:As the street is same so,

Mg/A=mg/a or M/A=m/a

i.e M/10^2=m/4×10^2

Therefore 4M=m

Now from centre of mass formula

x=MX1 +mX2/M+m

x=M(0) +4M×4/5M

x=16/5

x=3.2

Answer 2

Answer:

See the attachment

Good luck

Explanation: