a rod of length 5 cm lies along the principal axis of a concave mirror of focal length 10cm in such a way that the and father from the is 15 CM away from it find the length of the image
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Mirror Formula
➵ 1/f = 1/v + 1/u
[In a concave mirror, the focal length and the distance between object ans mirror is negative]
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➵ 1/(- 10) = 1/v + 1/(- 15)
➵ - 1/10 + 1/15 = 1/v
➵ (- 3 + 2)/30 = 1/v
➵ - 1/30 = 1/v
➵ v = - 30
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m = - v/u = h2/h1
➵ - v/u = h2/h1
➵ - (- 30)/(- 15) = h2/5
➵ - 2 × 5 = h2
➵ h1 = - 10
Image height is 10 cm [magnified] and real [due to "-" sign].
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Image h = 10 cm [real]
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Answer:
infinitely large
Explanation:
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