Question

A rod of length 5 m heated to 40°C. If the length increases to 7 m after some time. Find the expansion coefficient. Room temperature is 30°C.

Answer 1

Explanation:

Given :

Intital length Lo = 5m

Expanded length L = 7m

Change in length ∆L = 7 -5 = 2 m

Temperature difference∆T = 40° C - 30 °C = 10 °C

Absolute temperature T = 10°C + 273 = 283K

The linear expansion formula is given by ,

∆ L / Lo = aL ∆ T

Length of cofficient is given by

aL = ∆ L / Lo × ∆T

= 2 / 5 × 283

AL= 14× 10^-4 K -1

Hope it helps you