Question

A rod of length 'I and mass 'm' rotates about end 'A' in vertical plane as shown. Magnitude of normal
reaction by the hinge at 'A' is​

Answer 1

Answer:

the ans will be mg/4

N = normal reaction by A.

Answer 2

Given:

length of road l

mass = m

It rotates about end A

To find:

Magnitude of normal reaction by the hinge at A

Explanation:

τ = I∝

ml²/3 = mgl/2l

∝ = 3g/2l

a = ∝.r

∴ a = (3g/2l)×(l/2)  = 3g/4

  a = 3g/4

mg - Na = ma

N(A) - mg - m ×(3g/4)  = (3mg - mg)/4

N(A) = mg/4

Answer = mg/4