A rod of length ‘l’ and mass ‘m’ fixed at one end, is hanging vertically. The other end is now
raised so that the rod makes an angle 30° with horizontal line. The work done in this process
will be
(1) mgl (2) mgl/2
(3) mgl/3 (4) mgl/4
Answers
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Answer:
Explanation:
The work done in moving the centre of mass of rod ...
The work done is mgl/2/2 which is equal to mgl/4
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Concept introduction:
Work done is considered as the force acting on a particular medium with a specific time and distance. Work done is the process of acting foce on a body whenever it moves at a time.
Given:
We have been given the length and the mass along with the angle.
To find:
We have to find the work done in the process.
Solution:
According to the question,
Work done = (mgL/2)/2 = mgL/4
= mgL/4
Final answer:
Work done in the process is mgl/4
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