Question

A rod of length l and mass m rotates about end A in vertical plane as shown. Magnitude of normal reaction by the hinge at A is

Answer 1

Answer:

see the photo, the concept is to apply rotational equilibrium.

Please check the answer in your assignment book.

Hope you will be able to understand.

Answer 2

Answer:

mg/2.

Explanation:

From the rotational motion we get that torque which gets applied on all of the position will be product of the normal reaction and length of the given rod. Hence, we also get that the summation of all the torque will be equal to 0.

So, if we take that the rod is in equilibrium constant at the position B so, we will get the summation of the torque to be equal to the potential energy at the center of gravity of the rod. Which is N*L = mgL/2. Which on solving we will get that the normal reaction N = mg/2.