a rod of length l having charge q uniformly distributed moves towards right with constant speed v. at t equal to 0 it enters in an imaginary cube of edge l/2. sketch variation of electric flux passing through cube with respect to time
please give brief explanation with full calculation
Answers
Answered by
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t=0 to t=
2v
I
At any time t, length of rod inside cube
=vt
Charge inside cube =
I
q
vt
∴ϕ=
ε
0
q
In
=
ε
0
I
qv
t,ϕ∝t
Graph will be straight line of slope qv/ε
0
I
t=0,ϕ=0
t=
2v
I
,ϕ=
2ε
0
q
t=I/2v to t=I/v, half of rod inside cube, ϕ=
2ε
0
q
t=
v
I
to t=
2v
3I
Charge inside the cube,
q
In
=q−
I
q
(vt−
2
I
)
=
2
3q
−
I
qv
t
ϕ=
ε
0
(
2
3q
−
I
qv
t)
=
2ε
0
3q
−
ε
0
I
qv
t
The graph will be straight line of negative slope and positive intercept.
t=
v
I
, ϕ=
2ε
0
q
t=
2v
3I
, ϕ=0.
I HOPE IT HELPS U FRND ❣️❣️
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