Question

A rod of length l resting on a wall and the floor. Its lower end is pulled towards right with a constant velocity v. Find angular velocity of its rod

Answer 1

The angular velocity of the rod is vcotθ.

Explanation:

Here, distance from the corner to the point A is x and that up  to B is y. Then,

v=dx / dt

and

vB = −dy/dt

Further,  x^2 + y^2 = l^2

Differentiating with respect to time t

2x dx/dt + 2y dy/dt=0

xv = yvB

vB = x/yv = vcotθ

Thus the angular velocity of the rod is vcotθ.

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