Question

A rod of mass 2 kg and length 1 m is pivoted at one end A and kept on a smooth surface. A
particle of mass 500 gm strikes the other end B of the rod and sticks to the rod. If particle
was moving with the speed of 10 m/s, what is the angular speed of the rod after collision?​

Answer 1

Refer the attachment friend ↗️↗️

Answer 2

Answer:

Given = mass = 2Kg

             length = 1m

             particle mass = 500gm

             velocity = 10m/s

to find =  angular speed

solution=

τnet = 0

L= mvr

Li= 1/2 x 10 x1

Li = 5Kgm²/s

Lf = i.e ω= (ml²/3 + mp l²)ω

ω= 2 x 1 /3+ 1/2x1)ω

ω= 7/6ωKgm²/sec

7/6ω= 5

ω= 30/7

ω= 4.2rad / sec

so the angular speed is ω= 4.2rad / sec