A rod of mass M and length L is lying on a horizontal table.
Work done in making it stand on one end will be:
Answers
Answered by
12
Answer:Mgl/2
Explanation:
We need to concentrate on center of mass here
Center of mass is a point where we assume all the mass is concentrated
Matter of fact, at the center of any symmetrical center of a body
As the rod is sleeping on the floor
Energy stored is zero
When it's made to stand it's center of mass raised by L/2 distance high from ground
So work done is force *displacement
MgL/2 is the correct answer
Answered by
1
Explanation:
Here we might get confused that why taken at l/2 but it is fact that of symmetrical or uniform body we have assume it's whole mass at one place(COM)
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