Question

A rod of mass M, length L is hinged at point P and is free to rotate in a vertical plane as shown. It is released from rest when it is horizontal.Angular acceleration of rod initially is?
(figure and options for answer in attachement)​

Answer 1

Explanation:

(i)τ=Iα

So,

2

mgl

=

3

1

ml

2

(α)

⇒α=

2l

3g

(ii) Tangential acceleration of poit A=g

But as angular velocity of point is zero so, angular acceleration will be zero.

Answer 2

Answer:

(i)τ=Iα

So,

2  mgl

=

3  1  ml

2  (α)  ⇒α=

2l  3g

(ii) Tangential acceleration of poit A=g

But as the angular velocity of the point is zero so, angular acceleration will be zero.

Explanation:

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