Question

A rod of mass n and length l is hinged at one of its end A as shown in figure. A force F is applied at distance x from A. The instantaneous acceleration of center of mass a varies with x as​

Answer 1

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Answer 2

Answer:

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Explanation:

Let the force F be applied at a distance x from the hinged point.

Hence, τ==Iα=3mL2α    ...(1)

Since the cm is at a distance 2L from the hinged end, its acceleration a=2Lα

⇒α=L2a

Substituting α in (1)

Fx=3mL2α=3mL2L2a

⇒a=2mL3Fx

⇒a=(constant)x

The above is equation of a straight line.