Physics, asked by melissagan1363, 11 months ago

A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is(a) \frac{Wd}{x}(b) \frac{W(d-x)}{x}(c) \frac{W(d-x)}{d}(d) \frac{Wx}{d}

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Answered by adityarindhe50
31
hence the option b is correct
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