a rod roller is 2m long and its diameteris 112 cm how many revolution will it make to level a rod with area 7040 sq. m
Answers
Answered by
1
Step-by-step explanation:
r=d÷2
r=112÷2
r=56
LSA of cylinder=2πrh
=2×22÷7×56×2
=44÷7×112
Answered by
0
Answer:
8.68 revolution
Step-by-step explanation:
circumference of circle= 2pi R
i.e. 2*3.14*66=810.48cm
so to cover 7040 sq m
we need to divide it by it's circumference
i.e
7040/810.48
=8.68 revolutions
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