A rohmbus one of the diagnol 20cm
perimeter of the rohmbus 104cm
find the area.
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Answer:
480 cm²
Step-by-step explanation:
One diagonal of rhombus = 20 cm.
Perimeter = 104 cm.
Formula for perimeter of rhombus = 4 * Side
4 * Side = 104
=> Side = 104/4 = 26 cm.
In a rhombus the diagonals bisect each other at O.
=> AO = 20/2 = 10 cm. DO = BD/2.
So using Pythagoras theorem, calculate the
AD² = AO² + OD²
26² = 10² + OD²
OD = √676 - 100 = 576 = 24.
Thus full length of other diagonal = 2 * 24 = 48 cm.
Now area of rhombus = 1/2 * d₁ * d₂ = 1/2 * 20*48 = 480 cm²
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