a roller 140 cm long has a radius of 35 cm .to level the playground it takes 980 complete revolutions. determine the cost of levelling the playground at the rate of 75 paisa per square metre.
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roller surface area =2pi.r.h
where r is the radius of roller, and h is length of roller.
roller surface area =2x22/7x35x140
=30800cm^2
because roller complete 980revolution so, total area levelled by roller=30800x980cm^2=30184000cm^2
=3018.4m^2
now cost =3018.4x75/100 Rs=2263.8Rs
where r is the radius of roller, and h is length of roller.
roller surface area =2x22/7x35x140
=30800cm^2
because roller complete 980revolution so, total area levelled by roller=30800x980cm^2=30184000cm^2
=3018.4m^2
now cost =3018.4x75/100 Rs=2263.8Rs
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