a roller 140 cm long has a radius of 35 cm .to level the playground it takes 980 complete revolutions. determine the cost of levelling the playground at the rate of 75 paisa per square metre.
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cylindrical surface area of the roller = 140 cm * 2 π 35 cm
= 9800π cm² = area covered in one revolution of the roller.
total surface area of the ground = 980 * 9800 π cm² = 98 * 9.8 π m²
cost = Rs 0.75 * 9.8 * 0.98 * π = Rs 22.63
= 9800π cm² = area covered in one revolution of the roller.
total surface area of the ground = 980 * 9800 π cm² = 98 * 9.8 π m²
cost = Rs 0.75 * 9.8 * 0.98 * π = Rs 22.63
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