A roller coaster car with a mass of 1500 kg starts at rest from a point 62 m above the ground.
At point B, it is 17 m above the ground.
(a) What is the initial potential energy of the car?
(b) What is the potential energy at point B?
If the initial kinetic energy was zero and the work done against friction between the starting
point and point B is 8,000 J,
(c) what is the kinetic energy of the car at point B?
Use g = 9.8 m/s2
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The work done upon an object is found with the equation
W = F*d*cos(Theta)
In this case, the d=6.0 m; the F=24.5 N (it takes 24.5 N of force to lift a 2.5-kg object; that's the weight of the object), and the angle between F and d (Theta) is 0 degrees. Substituting these values into the above equation yields
W = F*d*cos(Theta) = (24.5 N)*(6 m)*cos(0) = ~150 J (147 J)
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