A roller coaster is moving at 25 m/s at the bottom of a hill. Three
seconds later it reaches the top of the hill moving at 10 m/s. What
was the acceleration of the coaster?
Answers
Answered by
12
Explanation:
5m/s2. Explanation: aavg= ΔvΔt=vf−vitf−ti. Where:- vf is the final velocity v i is the initial velocity tf is the final time ti is the ...
−5m/s2 Explanation: aavg=ΔvΔt=vf
Answered by
2
Answer:
i dont know the answer but very nice question
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