Question

A roller coaster is moving at 25 m/s at the bottom of a hill. Three seconds later and 150 meters later it is moving at 10 m/s. What is the deceleration of the roller coaster?

Answer 1

Answer:

−5m/s2

Explanation

aavg=ΔvΔt=vf−vitf−ti

Where:-

vf is the final velocity

vi is the initial velocity

tf is the final time 

ti is the initial time

The final velocity of the roller coaster is 10m/s (when it reached the top"t=3s"), and the initial velocity is 25m/s (when it started moving at the bottom "t=0s")

So 

vf=10m/s

vi=25m/s

tf=3s

ti=0s

aavg=10−253−0=−153